Welcome to WuJiGu Developer Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
1.4k views
in Technique[技术] by (71.8m points)

r - dplyr: lead() and lag() wrong when used with group_by()

I want to find the lead() and lag() element in each group, but had some wrong results.

For example, data is like this:

library(dplyr)
df = data.frame(name=rep(c('Al','Jen'),3),
                score=rep(c(100, 80, 60),2))
df

Data:

  name score
1   Al   100
2  Jen    80
3   Al    60
4  Jen   100
5   Al    80
6  Jen    60

Now I try to find out lead() and lag() scores for each person. If I sort it using arrange(), I can get the correct answer:

df %>%
  arrange(name) %>%
  group_by(name) %>%
  mutate(next.score = lead(score),
         before.score = lag(score) )

OUTPUT1:

Source: local data frame [6 x 4]
Groups: name

      name score next.score before.score
    1   Al   100         60           NA
    2   Al    60         80          100
    3   Al    80         NA           60
    4  Jen    80        100           NA
    5  Jen   100         60           80
    6  Jen    60         NA          100

Without arrange(), the result is wrong:

df %>%
  group_by(name) %>%
  mutate(next.score = lead(score),
         before.score = lag(score) )

OUTPUT2:

Source: local data frame [6 x 4]
Groups: name

  name score next.score before.score
1   Al   100         80           NA
2  Jen    80         60           NA
3   Al    60        100           80
4  Jen   100         80           60
5   Al    80         NA          100
6  Jen    60         NA           80

E.g., in 1st line, Al's next.score should be 60 (3rd line).

Anybody know why this happened? Why arrange() affects the result (the values, not just about the order)? Thanks~

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

It seems you have to pass additional argument to lag and lead functions. When I run your function without arrange, but with order_by added, everything seems to be ok.

df %>%
group_by(name) %>%
mutate(next.score = lead(score, order_by=name),
before.score = lag(score, order_by=name))

Output:

  name score next.score before.score
1   Al   100         60           NA
2  Jen    80        100           NA
3   Al    60         80          100
4  Jen   100         60           80
5   Al    80         NA           60
6  Jen    60         NA          100

My sessionInfo():

R version 3.1.1 (2014-07-10)
Platform: x86_64-w64-mingw32/x64 (64-bit)

locale:
[1] LC_COLLATE=Polish_Poland.1250  LC_CTYPE=Polish_Poland.1250        LC_MONETARY=Polish_Poland.1250
[4] LC_NUMERIC=C                   LC_TIME=Polish_Poland.1250    

attached base packages:
[1] stats     graphics  grDevices utils     datasets  methods   base     

other attached packages:
[1] dplyr_0.4.1

loaded via a namespace (and not attached):
[1] assertthat_0.1  DBI_0.3.1       lazyeval_0.1.10 magrittr_1.5                parallel_3.1.1  Rcpp_0.11.5    
[7] tools_3.1.1 

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to WuJiGu Developer Q&A Community for programmer and developer-Open, Learning and Share
...