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in Technique[技术] by (71.8m points)

Convert Json results into HTML form using ASP.NET Core 5 MVC

I want to display the balance related to a specific card when the Id is being selected from the dropdown select list and show the balance value in [enter image description here][1]input on a form.

But what I am getting is only the JSON results when I am running the program. my form is not appearing

The Test action in the controller:

public IActionResult Test()
{
    var data = from als in ctx.TbIstanbulCards select new { als.IstanbulCardId, als.Balance };
    return Json(data.ToList());
}

The Index view (Test)

@model VmIstanbul

@section Scripts{
    <script src="https://code.jquery.com/jquery-1.10.2.min.js"></script>

    <script>
        $(document).ready(function () {
            var options = {};
            options.url = "/Customer?handler=SelectAll";
            options.type = "GET";
            options.dataType = "json";
            options.success = function (data) {
                data.forEach(function (element) {
                    $("#customerid").append("<option>
        "
        + element.IstanbulCardId + "
    </option > ");
            });
            };
            options.error = function () {
                $("#msg").html("Error while
    making Ajax call!");
        };
            $.ajax(options);
        });

        $("#customerid").change(function () {
            var options = {};
            options.url = "/Customer/" +
                $("#customerid").val() + "?handler=SelectByID";
            options.type = "GET";
            options.dataType = "json";
            options.success = function (data) {
                $("#companyname").val(data.Balance);
                //$("#contactname").val(data.contactName);
                //$("#country").val(data.country);
            };
            options.error = function () {
                $("#msg").html("Error while making Ajax call!");
            };
            $.ajax(options);
        });


</script>

}
<form id="myForm" asp-controller="Customer" asp-action="Test">
    <label for="departmentsDropdown"><b>Card</b></label>
    <select class="form-control" onchange="getValue()" id="departmentsDropdown" name="departmentsDropdown"></select><br />
    <input type="text" value="" id="show" />
</form>

The result appear like that

https://i.stack.imgur.com/sqDVl.png


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1 Answer

0 votes
by (71.8m points)

It is not clear from your codes, since the ajax url is razor page route but not mvc. Do you enable both of them?

Besides, from your previous post I see that the View name is Test.cshtml, while the Test action return Json, so when you access /Custom/Test, you just get the Json results instead of a View.

If the Test action is used to display the html view, I think it should return View:

public IActionResult Test()
{
    return View();
}

Update:

Have an action(Test) to return View(Test.cshtml). Just reutn View() without any data since I didn't see any place you use the model(VmIstanbul) value in your view.

public IActionResult Test()
{
    
    return View();
}

Have another action to return data to ajax, Give it a name except Test. For example:

public IActionResult TestSelect()
{
    var data = from als in ctx.TbIstanbulCards select new { als.IstanbulCardId, als.Balance };
    return Json(data.ToList());
}

And change the ajax url to TestSelect

@section Scripts{
    <script src="https://code.jquery.com/jquery-1.10.2.min.js"></script>
    <script type="text/javascript">
        $(document).ready(function () {
            $.ajax({
                type: "GET",
                url: "/Customer/TestSelect",
                success: function (data) {
                    console.log(data);
                    var s = '<option value="-1">Please Select a Card id</option>';
                    for (var i = 0; i < data.length; i++) {
                        s += '<option value="' + data[i].balance + '">' + data[i].istanbulCardId + '</option>';
                    }
                    $("#departmentsDropdown").html(s);
                }
            })
        })

        function getValue() {
            var myVal = $("#departmentsDropdown").val();
            $("#show").val(myVal);
        }
    </script>
}

Result:

enter image description here


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