Regex match character with negative lookbehind of two chars

Question

I want to split a string using the character "/", but the split should only occur if there is no "" in front of it.

String:

/10/102-/ABC083.013/11/201201/20/83/30/463098194/32/7.7/40/0:20

Regex:

/*(?<!\)[^/]*/*(?<!\)[^/]*

Expected result:

/10/102-/ABC083.013
/11/201201
/20/83
/30/463098194
/32/7.7
/40/0:20

But with my regex I get:

/10/102-
/ABC083.013/11
/201201/20
/83/30
/463098194/32
/7.7/40
/0:20

online regex example

The issue is on the first group "/10/102-/ABC083.013", it does not recognize the string "/" to the first group. I don't know how to optimize/change my regex so that it recognizes the first group correctly.

Answer 1

You can use

(?:/[^\/]+){2}(?:\/[^\/]+)?

See the regex demo. Details:

• (?:/[^\/]+){2} - two occurrences of
  • / - a / char
  • [^\/]+ - one or more chars other than / and
• (?:\/[^\/]+)? - an optional occurrence of:
  • \ - a char
  • / - a / char
  • [^\/]+ - one or more chars other than / and